## Presentation on theme: "Problem 5.154 a 24 kN 30 kN The beam abdominal muscle supports two focused loads and rests on soil which exerts a linearly spread upward pack as shown. Determine."— Presentation transcript:

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1 difficulty 5.154 a 24 kN 30 kN The beam abdominal muscle supports two focused loads and also rests on floor which exerts a linearly distributed upward load as shown. Determine (a) the distance a for which wA = 20 kN/m, (b) the equivalent value wB. 0.3 m A B wA wB 1.8 m

2 **Solving troubles on Your own a **24 kN 30 kN 0.3 m The beam abdominal supports two focused loads and rests on floor which exerts a linearly dispersed upward fill as shown. Identify (a) the street a because that which wA = 20 kN/m, (b) the corresponding value wB. A B wA wB 1.8 m 1. Replace the spread load through a single equivalent force. The size of this force is equal to the area under the distributed load curve and its line of activity passes through the centroid of the area. 2. Once possible, facility distributed tons should be split into common shape areas.

3 **RII = (1.8 m)(wB kN/m) = 0.9 wB kN**Problem systems a 24 kN 30 kN 0.3 m change the distributed load through a pair of identical forces. C A B 20 kN/m wB 0.6 m 0.6 m RI RII 1 2 We have RI = (1.8 m)(20 kN/m) = 18 kN 1 2 RII = (1.8 m)(wB kN/m) = 0.9 wB kN

4 **SFy = 0: -24 kN + 18 kN + (0.9 wB) kN - 30 kN= 0 or wB = 40 kN/m**Problem equipment a 24 kN 30 kN 0.3 m C A B wB 0.6 m 0.6 m RI = 18 kN RII = 0.9 wB kN (a) + SMC = 0: (1.2 - a)m x 24 kN m x 18 kN - 0.3m x 30 kN = 0 or a = m (b) + SFy = 0: -24 kN + 18 kN + (0.9 wB) kN - 30 kN= 0 or wB = 40 kN/m

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