#\"\"_84^218\"Po\"# experience alpha decay and also beta minus decay.https://en.wikipedia.org/wiki/Isotopes_of_polonium

Alpha Decay

In alpha decay, an rough nucleus will emit an alpha particle, i beg your pardon is a helium nucleus written of two protons and also neutrons. The mass number of the daughter isotope will be lessened by four, and also the atom number will be diminished by 2.

You are watching: To what element does polonium-208 (atomic number 84) decay when it emits an alpha particle? The alpha degeneration of #\"\"_84^218\"Po\"# produce #\"\"_82^214\"Pb\"#.

#\"\"_84^218\"Po\"##rarr##\"\"_82^214\"Pb\" + \"\"_2^4\"He\"#

Beta Minus Decay.

In beta minus decay, a neutron in an turbulent nucleus decays into a proton, an electron, and an antineutrino: #\"n\"^0\"##rarr##\"p\"^(+) + e^(-) + barnu_e# The daughter isotope will have actually the exact same mass number, but the atomic number increases by one.

The beta minus decay of #\"\"_84^218\"Po\"# produce #\"\"_85^218\"At\"#.

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#\"\"_84^218\"Po\"##rarr##\"\"_85^218\"At\"+e^(-)+barnu_e# Jacob T.
Jul 25, 2018
#A\" = 218# and also #Z\" = 85# when #color(white)(l)_84^218 \"Po\"# undergoes beta minus decay.
Explanation:

An atom publication an electron (#e^(-)#) as it undergoes beta minus decay. A neutron (a subatomic particle of #A = 1#, #Z = 0#) is convert to a proton (#A = 1#, #Z = 1#) in this process:

#color(white)(l)_0^1 n^(0) come color(white)(l)_1^1 p^(+) + e^(-)#

Thus for each electron (beta minus particle) emitted, the atomic number of the atom boost by one vice versa, its massive number stays the same. As such one would suppose the beta minus degeneration product the #color(white)(l)_84^218 \"Po\"# to it is in of

mass number #A\" = A = 218# andatomic number #Z\" = Z + 1 = 85#

An atom emits a ceiling helium cell core (\"alpha particle\" #color(white)(l)_2^4 \"He\"# for which #A = 4# and #Z = 2#) as it undergoes alpha decay.

The alpha particle contains two protons bonded to two neutrons, all of the four nucleons are straight removed indigenous the parental nucleus (#color(white)(l)_84^218 \"Po\"# in this case.) therefore the atomic number #\"Z\"# that the daughter cell core of the alpha degeneration shall be smaller sized than the of the parental nucleus by #2# vice versa, the massive number #\"A\"# smaller sized by #2 + 2 =4#. Therefore the daughter nuclei created in the alpha degeneration of #color(white)(l)_84^218 \"Po\"# would certainly have