If we evaluate this expression, we square everything in the an initial set of parentheses; this means we have actually 10²n² - 1², or 100n² - 1.

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This is the expression we were trying come equal.



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The expression 100n² - 1 is tantamount to (10n)² - 1² .

Step-by-step explanation:

As offered the expression in the question be as follow

= 100n² - 1

Take

= (10n)² - 1²

As

(10n)² = 100n²

1² = 1

Put in these worths in the expression

= (10n)² - 1²

= 100n² - 1

Therefore the expression 100n² - 1 is indistinguishable to (10n)² - 1² .


The simplified form is

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Step-by-step explanation:

Given the expression

we need to simplify the over expression.

Expression:

As

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which is compelled simplified form.

Option 1 is correct


You know that

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.

Use the residential or commercial property

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come state that

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Then the expression

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is indistinguishable to

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correct selection is A.

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Which expression is identical to 100 n2 − 1? (10n)2 − (1)2 (10n2)2 − (1)2 (50n)2 − (1)2 (50n2)2 − (1)2Regroup:100n^2-1=10^2n^2-1=(10n)^2-1^2So the exactly answer is : (10n)^2-1^2To effort to variable a polynomial of 4 or an ext terms v no typical factor, an initial rewrite that in groups. Each group may perhaps be individually factored, and also the result expression might possibly lend itself to more factorization if a greatest typical factor or special kind is created.
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